Posts

Showing posts from June, 2010

Technical Tip of The Week

TECHNICAL TIP OF THE WEEK – Drywall 06302010 Problem: Determine the amount of drywall (sheetrock) needed to sheetrock (drywall) a room measuring 16’ feet x 25’ feet with a 10’ foot ceiling. We will see later that the height of the ceiling is an important factor. Using the following formula, find the number of sheets required. Formula: 16’ + 16’ + 25’ + 25’ = 82’ linear feet 82’ l.f. x 10’ (ceiling height) = 820 square feet 820 s.f. / 40 s.f. (1 sheet of drywall 4’ wide x 10’ tall) = 20.5 sheets Always good to add about 5% for damage and waste (amounts may vary depending on job conditions) To add the ceiling quantity use the following method Formula: 16’ x 25’ = 400 s.f. 400 s.f. / 40s.f. = 10 sheets Solution: The room will require 31 sheets

26th Street Development

Sit back relax and enjoy the show...see how what we do can help you..... 26th Street Development View more presentations from Eric Godbolt .